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Sagot :

Réponse :

1) f(x) = (-3x+5)(-5x+4)+(5-3x)(x+2)

f(x) = (-3x+5)(-5x+4+x+2)

f(x) =(-3x+5)(-x+6)

g(x) = (3x-5)²

2) f(x) = 0

(-3x+5)(-x+6)=0

-3x+5=0

-3x=-5⇔x=5/3

-x+6=0⇔-x=-6⇔x=6

(3x-5)²

3x-5=0⇔3x=5⇔x=5/3

3a) x≠0⇒x≠5/3

b)(3x-5)(5x-4)+(5-3x)(x+2)/(3x-5)(3x-5)=

(5x-4)+(5-3x)(x+2)/(3x-5)=

(5x-4)+(5-3x)(x+2)/-1(3x-5)=

(5x-4)+(x+2)/-1=(-6x+2)/-1=-2(3x+1)

c) 2(3x+1)=0

3x+1=0⇔3x=-1⇔x=-1/3

Explications étape par étape

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