Réponse
factoriser (=(x−1)⋅(2⋅x+5)+4⋅x2+20⋅x+25)
factoriser (=(x-1)⋅(2⋅x+5)+4⋅x2+20⋅x+25)==(x−1)⋅(2⋅x+5)+4⋅x2+20⋅x+25=(x-1)⋅(2⋅x+5)+4⋅x2+20⋅x+25
