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Sagot :

ZAHIHANAA102

Explications:

1/

16-(x+3)²

16-( x² + 2×x×3 +3²)

16-(x²+6x+9)

16-x²-6x-9

-x² -6x +7

2/

16-(x+3)²=0

4²-(x+3)²=0

(4+x+3)(4-x-3)=0

(x+7)(1-x)=0

x+7=0 ou 1-x =0

x=-7 ou -x = -1

x = -7 ou x =1

إذن الأعداد-7 و 1 هم حلول هذه المعادلة

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