Voici mon raisonnement :
S1 = alpha D - alpha C + alpha C - alpha A
= alpha A - alpha D
= (BD,BA)
S2 = alpha A - alpha C + Alpha D - alpha C
= alpha D - alpha A
= (CA,AD)
S3 = alpha A - alpha D + alpha C - alpha A + alpha D - alpha B
= alpha B - alpha C
= (BC,AB)