Réponse :
Bonjour,
[tex]2 + x(2x + 1) = 5x + 2\\\\2 + 2x^2 + x = 5x + 2\\\\2x^2 + x - 5x = 2 - 2\\\\2x^2 - 4x = 0\\\\2x(2x - 2) = 0[/tex]
Or A × B = 0 ⇔ A = 0 ou B = 0
[tex]2x = 0\\\\x = 0[/tex]
[tex]2x - 2 = 0\\\\2x = 2\\\\x = 1[/tex]
Donc S = {0 ; 1}
