bonjour
x² = 3
x = √3 ou - √ 3
x² + 25 = 14
x² + 25 = 14 - 25
x² = - 11 ⇔ pas de solution dans R
x²/3 + 3 /3 = 3/3
x² = 3 - 3
x² = 0
x = 0
3 x² = 12
x² = 4
x = √4 ou - √4
x = 2 ou - 2
( 2 x - 3 )² = 4
( 2 x - 3 )² - 4 = 0
( 2 x - 3 - 2 ) ( 2 x - 3 + 2 ) = 0
( 2 x - 5 ) ( 2 x - 1 ) = 0
x = 5/2 ou 1 /2
( x - 3 )² = 4
( x - 3 )² - 4 = 0
( x - 3 - 2 ) ( x - 3 + 2 ) = 0
( x - 5 ) ( x - 1 ) = 0
x = 5 ou 1
