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Sagot :

CO0309

Réponse:

Bonsoir,

[tex]m = \sqrt{18} + 3 \sqrt{2} + 2 \sqrt{50} \\ = 16 \sqrt{2} [/tex]

[tex]h = \sqrt{ \frac{49}{9} } \times ( \sqrt{3} ) {}^{2} \\ = 7[/tex]

[tex]a = \sqrt{3 + \sqrt{5} } \times \sqrt{3 - \sqrt{5} } \\ = 2[/tex]

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