Réponse :
D = x(2-x)(x+3) - x(x-3)(2-x)
D = x(2-x) [(x+3) - (x-3)]
D= x(2-x) (x + 3 - x + 3)
D = 6x(2-x)
E= (x+7)² +2(x+7)²
E = (x+7)² (1+2)
E = 3(x+7)²
F = x²y + 6xy² -2xy
F = xy(x + 6y -2)
G= t²/4 - t + 1 = (t/2 - 1)²
H= 2x² +2√2x +1 = (x√2 +1)²
I = 4a² + 4√3a +3 = (2a + √3)²
J = 4x² -25 - (2x-5)(x+8)
J = (2x-5)(2x +5) - (2x-5)(x+8)
J = (2x-5)[(2x +5) -(x+8)]
J =(2x-5)(2x +5 -x -8)
J = (2x-5)(x -3)
N = (1/4)x -3/8 + (2x-3)²
N= 1/8( 2x -3) + (2x-3)²
N = ( 2x -3) (1/8 +2x -3)
N= (2x -3) ( 2x +(1-24)/8)
N= (2x -3)(2x -23/8)
j'espère avoir aidé.
