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Sagot :

(f(g(x)))'=g'(x) * f'(g(x))

 

 

h(x)=e(racine(x))

 

h'(x)=1/(2racine(x)) * e(racine(x))=e(racine(x))/2racine(x)

 

i(x)=e(1/x)

 

Donc i'(x)=-1/x² * e(1/x)=-e(1/x)/x²

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