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Sagot :

Bonjour

1)

f (x) = (x + 3)² - 25

f (x) = x² + 6x + 9 - 25

f (x) = x² +  6x - 16

2)

f (x) = (x + 3)² - 25

f (x) = (x + 3)² - (5)²

f (x) = (x + 3 - 5) (x + 3 + 5)

f (x) = (x - 2) (x + 8)

3)

a)

f (x) = 0

(x- 2) (x + 8) = 0

x - 2 = 0          ou           x + 8 = 0

x = 2                               x = - 8

b)

f (x) = - 16

x² +  6x - 16 = - 16

x² + 6x - 16 + 16 = 0

x² + 6x = 0

x (x + 6) = 0

x = 0                      ou          x + 6 = 0

                                           x = - 6

c)

f (x) = 11

x² +  6x - 16 = 11

x² + 6x - 16 - 11 = 0

x² + 6x - 27 = 0

(x - 3) (x + 9) = 0

x - 3 = 0               ou        x + 9 = 0

x = 3                                 x = - 9.

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