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Bonjour,

J’ai besoin d’aide en maths pour ces deux équations du second degré.

1) -x^2 + x + 1 = 3x - 7


2) x^2 - x - 9 = x + 2



Merci d’avance

Sagot :

Bonjour,

1) -x² + x + 1 = 3x - 7

-x² + x - 3x + 1 + 7 = 0

-x² - 2x + 8 = 0

∆ = b² - 4ac = 4 - 4 × (-1) × 8 = 36

x1 = (-b -√∆)/2a = (2 - 6)/(-2) = (-4)/(-2) = 2

x2 = (-b + √∆)/2a = (2 + 6)/(-2) = 8/(-2) = -4

2) x² - x - 9 = x + 2

x² - x - 9 - x - 2 = 0

x² -2x - 11 = 0

∆ = b² - 4ac = 4 - 4 × 1 × (-11) = 48

x1 =( -b -√∆)/2a = (2 - √48)/2 = 1 - 2√3

x2 = (-b + √∆)/2a = (2 + √48)/2 = 1 + 2√3

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