Sagot :
Réponse :
1. [tex]\frac{2}{3}[/tex] ( 2 + [tex]\frac{3}{4}[/tex] ) = [tex]\frac{2}{3}[/tex] × 2 + [tex]\frac{2}{3}[/tex] × [tex]\frac{3}{4}[/tex]
= [tex]\frac{4}{3}[/tex] + [tex]\frac{6}{12}[/tex]
= [tex]\frac{16}{12}[/tex] + [tex]\frac{6}{12}[/tex] meme denominateur
= [tex]\frac{22}{12}[/tex] = [tex]\frac{11}{6}[/tex]
2. [tex]\frac{2}{3}[/tex] × 2 + [tex]\frac{3}{4}[/tex] = [tex]\frac{4}{3}[/tex] + [tex]\frac{3}{4}[/tex]
= [tex]\frac{16}{12}[/tex] + [tex]\frac{9}{12}[/tex]
= [tex]\frac{25}{12}[/tex]
3. [tex]\frac{1}{2}[/tex] + [tex]\frac{1}{3}[/tex] - [tex]\frac{1}{6}[/tex] = [tex]\frac{3}{6}[/tex] + [tex]\frac{2}{6}[/tex] - [tex]\frac{1}{6}[/tex]
= [tex]\frac{4}{6}[/tex] = [tex]\frac{2}{3}[/tex]
4. [tex]\frac{1}{2}[/tex] ÷ [tex]\frac{1}{3}[/tex] ÷ [tex]\frac{1}{4}[/tex] ÷ [tex]\frac{1}{5}[/tex] = [tex]\frac{1}{2}[/tex] × [tex]\frac{3}{1}[/tex] ÷ [tex]\frac{1}{4}[/tex] ÷ [tex]\frac{1}{5}[/tex]
= [tex]\frac{3}{2}[/tex] × [tex]\frac{4}{1}[/tex] ÷ [tex]\frac{1}{5}[/tex]
= [tex]\frac{12}{2}[/tex] × [tex]\frac{5}{1}[/tex]
= [tex]\frac{60}{2}[/tex] = 30