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Sagot :

SKABETIX

Bonjour,

x^2 + 2x - 3 = 0

On a a = 1 ; b = 2 et c = - 3

∆ = b^2 - 4ac = 2^2 - 4 × 1 × (-3) = 4 + 12 = 16 > 0

Il y a donc deux racines dans R :

X1 = (-b -√∆)/2a = (-2 - 4)/2 = -6/2 = -3

X2 = (-b + √∆)/2a = (-2 + 4)/2 = 2/2 = 1

On a donc S = {-3 ; 1}

KAVITHA01

Réponse:

Bonjour,

x²2+2x-3=0

(x-1) (x+3)=0

x-1=0 or x+3=0

x=1 or x=-3

Donc {-3 ; 1}

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