Sagot :
Réponse :
Hello
32x^-4 = 8x^-6
32x^-4-8x^-6=0; x≠0
32×[1/x⁴]-8[1/x^6]=0
32/x⁴-8/x^6=0
(32x²-8)/x^6=0
32x²-8=0
32x²=8
x²=8/32=1/4
x==1/2
Ou x==-1/2
Les solutions finale sont
[tex]x_1=1/2 , x_2=-1/2[/tex]
Hi !
First of all, we need to get rid of those minus next to the power.
To do that, use this rule : [tex]x^{-a} = \frac{1}{x^a}[/tex]
You will get : [tex]\frac{32}{x^4} = \frac{8}{x^6}[/tex]
Now, we need to get rid of those fractions : use the rule of cross-multiplication.
You will get : [tex]32x^6 = 8x^4[/tex]
Now move [tex]8x^4[/tex] on the left and factorize.
You will get an equation with product which is equals to 0
Now you can solve it easily !
Hope it helped (sorry if I did some English mistakes i'm French)