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Sagot :

SVANT

Réponse:

On utilise la linearité de l'integrale.

I = ∫ 7f(x)dx = 7×∫ f(x)dx = 7×3 = 21

J = ∫ ½g(x)dx = ½∫ g(x)dx = ½×(-2) = -1

K = ∫ (4f(x) - 5g(x))dx = 4∫f(x)dx -5∫g(x)dx

K = 4×3 - 5×(-2)

K = 22

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