bonjour
programme
1
1² = 1
1 + 5 = 6
6 *1 = 6
6 + 3 = 9
9
x
x²
x² + 5
x ( x² + 5 )
x ( x² + 5 ) + 3 x
A = x ³ + 5 x + 3 x
A = x ³ + 8 x
B = x ( x² + 8 )
B = x ³ + 8 x
donc B = A
si x = 1 , B = 1 + 8 = 9
C = 7 ( x ³ + x ) - x ( 6 x² - 1 )
C = 7 x ³ + 7 x - 6 x ³ + x
C = x³ + 8 x
donc C = B
pour x = - 1
C = ( - 1 )³ + 8 *-1
= - 1 - 8 = - 9
