bonjour
programme 1
x
3 x
3 x + 1
A (x) = 3 x + 1
programme 2
x
x - 1
x
x + 2
( x - 1 ) ( x + 2 )
B (x) = ( x - 1 ) ( x + 2 )
pour obtenir 0 avec p 1
3 x + 1 = 0
3 x = - 1
x = - 1/3
B(x) = ( x - 1 ) ( x + 2 )
B (x) = x² + 2 x - x - 2 = x² + x - 2
B (x) - A (x) = ( x + 1 ) ( x - 3 )
( x + 1 ) ( x - 3 ) = x² - 3 x + x - 3 = x² - 2 x - 3
( x - 1 ) ( x + 2) - ( 3 x + 1)
= x² + 2 x - x - 2 - 3 x - 1
= x² - 2 x - 3
tu poses l'équation 3 x + 1 = ( x - 1) ( x + 2)
