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Sagot :

AYUDA

C = (3-4x) (3-4x) - 5(3-4x)

facteur commun : (3-4x)

C = (3-4x) (3-4x -5)

C = (3-4x) (-4x-2)

C = -2 (3-4x) (2x + 1)

D = il faut penser à a² - b² = (a+b) (a-b)

= 8² - (5x)² = (8-5x) (8+5x)

E - idem..

E = (4x)² - (2x-1)² = (4x+2x-1) (4x-(2x-1) = (6x-1) (2x+1)

VINS

bonjour

apprends ta leçon, ça aide  

C = ( 3 - 4 x ) ( 3 - 4 x -  5)

= ( 3 - 4 x ) ( - 4 x - 2 )

=  2 ( 3 - 4 x )  ( - 2 x - 1 )

D =  ( 8 - 5 x ) ( 8 + 5 x ) = identité remarquable

E = (  4 x + 2 x - 1 ) ( 4 x - 2 x + 1  )

= (  6 x - 1 ) ( 2 x + 1 )

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