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bonjour

F(x)=(x-2)(x+1)+(x-2)(2x+3)

F (x) = ( x - 2 ) ( x + 1 + 2 x + 3 )

F (x) =  ( x - 2 ) ( 3 x + 4 )

Bonjour,

F(x) = (x-2)(x+1)+(x-2)(2x+3)

      = x²+x-2x-2+2x²+3x-4x-6

      = 3x²-2x-8

F(x) = (x-2)(x+1)+(x-2)(2x+3)

      = (x-2)[(x+1)+(2x+3)]

      = (x-2)(3x+4)

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