Sagot :
Réponse :
bonsoir
résoudre
3x-4y=-1
-2x+5y=2
-2×3x-(-2)×4y=-2×(-1)
-6x+8y=2
-3×(-2x)+(-3)×5y=-3×2
6x-15y=-6
6x-6x=0
8y-15y=-7y et 2-6=-4
donc -7y=-4
y=4/7
3x-4(4/7)=-1
3x-16/7=-1
3x=-1+16/7=9/7
x=9/7÷3=3/7
solution x=3/7 et y =4/7
-4x+3y=2
-2x+5y=-3
2×(-4x)+2×3y=2×2
-8x+6y=4
-4×(-2x)+(-4)×5y=-4×(-3)
8x-20y=12
-8x+8x=0
6y-20y=-14y
4+12=16
-14y=16
y=16/-14=-8/7
-4x+3×-8/7=2
-4x-24/7=2
-4x=2+24/7
-4x=38/7
x=38/7÷(-4)=-19/14
solution x=-19/14 et y=-8/7
3x-y=1
-2x+3y=2
2×3x-2×y=2×1
6x-2y=2
3×(-2x)+3×3y=2×3
-6x+9y=6
-2y+9y=7y
2+6=8
7y=8
y=8/7
3x-8/7=1
3x=1+8/7
3x=15/7
x=15/7÷3=5/7
solution x=5/7 et y =8/7
Explications étape par étape
Réponse :
Bonsoir,
Explications étape par étape
1) Par combinaison linéaire
[tex]\left\{\begin {array} {ccc|c|c}3x-4y&=&-1&5&2\\-2x+5y&=&2&4&3\\\end{array}\right.\\\\\\\left\{\begin {array} {ccc}7x&=&3\\\\7y&=&4\\\end{array}\right.\\\\\\\boxed{\left\{\begin {array} {ccc}x&=&\dfrac{3}{7}\\\\y&=&\dfrac{4}{7}\\\end{array}\right.\\}\\[/tex]
2) Méthode de Cramer
[tex]\left\{\begin {array} {ccc}-4x+3y&=&2\\-2x+5y&-3\\\end{array}\right.\\\\\\\Delta=\left\\\begin{array}{|cc|}-4&3\\-2&5\\\end{array}\right. = -10+6=-14\\\\\\\Delta_1 =\left\\\begin{array}{|cc|}2&3\\-3&5\\\end{array}\right. = 10+9=19\\\\\\\Delta_2 =\left\\\begin{array}{|cc|}-4&2\\-2&-3\\\end{array}\right. =12+4=16\\\\\\\boxed{\left\{\begin{array}{ccc}x&=-&\dfrac{19}{14}\\\\y&=-&\dfrac{16}{14}\\\end{array}\right.\\}\\[/tex]
3) Par élimination
[tex]\left\{\begin{array}{ccc}3x-y&=&1\\-2x+3y&=&2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&3x-1\\-2x+3(3x-1)&=&2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}7x&=&5\\\\y&=&3*\dfrac{5}{7} -1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x&=&\dfrac{5}{7} \\\\y&=&\dfrac{8}{7}\\\end{array}\right.\\\\[/tex]
d) équation impossible
[tex]\left\{\begin{array}{ccc}3x-2y&=&-1\\\\-3x+2y&=&2\\\end{array}\right.\\\\\\Somme\ des\ 2\ \' equations\\0*x+0*y=1 \Longrightarrow\ 0=1\ impossible[/tex]