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Soit=N=(5x+3)puissance2-(5x+3)(7x-2) 1) développer et réduire N 2) factoriser N 3)Calculer N pour x=-4

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ISAPAUL

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(5x+3)² - (5x+3)(7x-2) = (5x+3)(5x+3) -(5x+3)(7x-2) = (5x+3)( 5x+3-7x+2)

= (5x+3)(-2x+5) forme factorisée 

= -10x² +25x -6x +15 = -10x² +19x +15

si x = 4

f(4)= -160 + 76 +15 = 69 

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