Sagot :
Factoriser l'expression :
A(x) = 2(3x+3)au carré + 6+2x
=2*9(x+1)²+2(3+x)
=18(x²+2x+1)+6+2x
=18x²+38x+24
=2(9x²+19x+12)
A(x) = 2(3x+3)au carré + 6+2x
=2*9(x+1)²+2(3+x)
=18(x²+2x+1)+6+2x
=18x²+38x+24
=2(9x²+19x+12)
A(x)=2(3x+3)²+6+2x
A(x)=2(9x²+18x+9)+6+2x
A(x)=18x²+36x+18+6+2x
A(x)=18x²+38x+24
A(x)=2(9x²+19x+12)
A(x)=2(9x²+18x+9)+6+2x
A(x)=18x²+36x+18+6+2x
A(x)=18x²+38x+24
A(x)=2(9x²+19x+12)
