a) f'(x)=3*3x^2-4*2x+11=9x^2-8x+11
b) f'(x)=(2x^2-3)'(3x-1)-(2x^2-3)(3x-1)'/(3x-1)^2=(2*2x)(3x-1)-(2x^2-3)*3/(3x-1)^2=(12x^2-4x-6x^2+9)/(3x-1)^2=(6x^2-4x+9)/(3x-1)^2
c) f'(x)=(5x-4)'(x+2)+(5x-4)(x+2)'=5(x+2)+(5x-4)=5x+10+5x-4=10x+6
d) f´(x)=8*(2x^2+5)'*(2x^2+5)^7=8(2*2x)*(2x^2+5)^7=32x(2x^2+5)^7