equation a resoudre : (x-2) (3x-8) = 14x
"x" représentant l'inconnue
Merci a tous bon week end


Sagot :

Bonjour,

(x - 2)(3x - 8) = 14x
3x^2 - 8x - 6x + 16 = 14x
3x^2 - 14x - 14x + 16 = 0
3x^2 - 28x + 16 = 0

Delta = (-28)^2 - 4 * 3 * 16
Delta = 784 - 192
Delta = 592
Vdelta = V592 = 24,33... > 0 donc deux solutions

X1 = (28 - 24,33)/(2*3) = 3,67/6 = 0,61
X2 = (28 + 24,33)/6 = 52,33/6 = 8,72