Il faut que u = kv ou encore que (m+4;m-2) = k(2m+2;m-1)
vérifie le signe de 2m+2 j'ai mis + car tu n'avais rien mis
(m+4;m-2) = k(2m+2;m-1)=> m+4 = k(2m+2) et m-2 = k(m-1)
=> k = (m+4)/2(m+2) = (m-2)/(m-1) => (m+4)(m-1) = (2m+2)(m-2)
=> m² + 3m - 4 = 2m² -2m-4 => m² - 5m = 0 => m(m-5) = 0 => m = 5 ou m = 0
