Sagot :
k(4;-1) il me semble car tu a k((xb+xa)/2 ; (yb+ya)/2)
Donc ((3+5)/2 ; (-4+2)/2)
((8/2) ; (-2/2))
(4;-1)
Donc ((3+5)/2 ; (-4+2)/2)
((8/2) ; (-2/2))
(4;-1)
1) k miliieu de [AB] <=> x= xa+xb/2
y=ya+yb/2
<=> x=3+5/2
y=2+(-4)
<=>x=4
y=-1
2)CA =√(3-(-2))²+(2-(-3))²
=√25+25
= 5√2
CB =√(5-(-2))²+(-4-(-3))²
=√49+1
= 5√2