SBENMOSTEFA
Answered

Développer réduire et ordonner, ensuite factoriser A(x):

 

A(x)=x²-1+(2x-1)(x+1)

 

Merci d'avance,

Sagot :

AZAXTRA

A(x) = x²-1+(2x-1)(x+1)

        = x² - 1 + 2x² + x - 1

        = 3x² + x - 2

 

A(x) = x²-1+(2x-1)(x+1)

        = (x-1)(x+1)+(2x-1)(x+1) 

        = (x+1)(x-1+2x-1)

        = (x+1)(3x-2)

WINNER123

A = x²-1 + (2x²+2x-x-1)

A = x²-1+2x²+2x-x-1

A = 3x² +x -2

 

factorisation

A = (x+1)(x- 1)+(2x-1)

= (x+1)(x-1+2x-1)

= (x+1)(3x-2)