Bonsoir,
On fait :
a)[tex](x+3)^2=36\\ (x+3)^2-6^2=0\\ (x+3-6)(x+3+6)=0\\ (x-3)(x+9) = 0\\ S = \left\{3 ; -9 \right\}[/tex]
b)[tex](3x-5)^2=(6-x)^2\\ (3x-5)^2-(6-x)^2 = 0\\ \left[(3x-5)-(6-x)\right]\left[(3x-5)+(6-x)\right]=0\\ (4x-11)(2x+1) = 0\\ S = \left\{\frac{11}{4} ;- \frac{1}{2}\right\}[/tex]
c)[tex]9x^2+4=12x\\ 9x^2-12x+4 = 0\\ (3x+2)^2 = 0\\ 3x+2 = 0\\ x = -\frac{2}{3}\\ S = \left\{-\frac{2}{3}\right\}[/tex]
d)[tex]25x^2=10x-1\\ 25x^2-10x+1 = 0\\ (5x-1)^2 = 0\\ 5x-1= 0\\ x = \frac{1}{5}\\ S = \left\{\frac{1}{5}\right\}[/tex]
