en utilisant la double distributivite , developpez les expressions suivantes classe de 3eme (2Y+7) (10+3Y) = (z+3) ( 3Z - 19) = ( - 5 h + 7 ) ( 2h - 21 ) + ( h + 8 ) ( h + 19 )= ( m + 41 ) (12 m -32) - ( m +28 ) (3 m +1 ) = ( 12d - 41 ) ( d - 33) - d ( 13d + 121 ) = 6 ( x + 3 ) ( 2 X - 7) = aider moi svp merci
20y+6y²+70+21y = 6y²+41y+70
3z²-19z+9z-57 = 3z²-10z-57
-10h²+105h+14h-147 +h²+19h+8h+152 = -9h²+146h +5
12m²-32m+492m-1312 - 3m²-m-84m-28 = 9m²+375m-1424
12d²-396d-41d+1353 -13d²-121d = -d² - 558d +1353
6x+18(2x-7) = 12x² -42x +36x -126
= 12x² -6x -126