(3x - 7)² < (5x + 3)²
(3x - 7)² - (5x + 3)² < 0
(3x-7 - 5x - 3)(3x-7+ 5x+ 3) < 0
(-2x-10)(8x-4)<0 je suppose que tu as vu le signe de la fonction du 2d d°.
x -5 1/2
f(x) - 0 + 0 - solution: -infini; -5[ ou ]1/2; infini
3x-1/5x >=1/x
(3x-1)/5x - 1/x >=0
(15x - 5 -1)/5x >=0
(15x - 6 ) / 5x >=0
x 0 2/5
f(x) + | - 0 + solution -infini; 0[ ou [2/5; infini
