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exercice 1: développer, réduire et ordonner.

 

A= (x +1) (x -3)

 

B=(2x -4) (x +2)

 

exercice 2: résoudre les équations ci-dessous :

 

2x - 5 = x +2

 

[tex]\frac{1}{2}[/tex]x +2 = 6

 

Merci pour votre aide

 

 

Sagot :

SULKY
Bonjour, 

A= (x +1) (x -3)
A = x² - 3x + x - 3
A = x² - 2x - 3

B=(2x -4) (x +2)
B = 2x² + 4x - 4x - 8
B = 2x² - 8


2x - 5 = x +2
2x - x = 2 + 5
x = 7 

1/2x +2 = 6
1/2x = 6 - 2
x = 4 * 2
x = 8
Bonsoir,

A = (x + 1)(x - 3)
A = x^2 - 3x + x - 3
A = x^2 - 2x - 3

B = (2x - 4)(x + 2)
B = 2x^2 + 4x - 4x - 8
B = 2x^2 - 8

Exercice 2 :

2x - 5 = x + 2
2x - x = 2 + 5
x = 7

x/2 + 2 = 6
x/2 = 6 - 2
x/2 = 4
x = 4 * 2
x = 8

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