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Sagot :

(x²+7x-3)-(3x-5x²-6=

= x^2+5x^2+7x-3x-3+6

=6x^2+4x+3

 

3y²-(3y-9)-(2y²-4y-5)

=3y^2-2y^2-3y+4y+9+5

= y^2+y+14

 

VOila, bon courage.
1) (x^2+7x-3)-(3x-5x^2-6) = x^2+7x-3-3x+5x^2+6 = 6x^2+4x+3 2) 3y^2-(3y-9)-(2y^2-4y-5) =3y^2-3y+9-2y^2+4y+5 =y^2+y+14

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