Sagot :
1. E = 9x²-25+(3x-5)(2x+15) = 15x²+35x-100
2. 9x²-25 = (3x-5) (3x+5)
3. E = 5(x+4)(3x-5)
bonsoir
on considere E=9x²-25+(3x-5)(2x+15)
1 develloper et redurie E
2 factoriser 9x²-25
3 en deduire une factorisation de E
1. E = 9x²-25+(3x-5)(2x+15) = 15x²+35x-100
2. 9x²-25 = (3x-5) (3x+5)
3. E = 5(x+4)(3x-5)