ANYAH25RSL ANYAH25RSL Mathématiques Answered (72) Developper les expressions suursarites 1=(x-2)(x+3) 2= (x+2)(x-1) 3 = 3-(3-(2-2)] - [4 7(2 +22)] 4= 5(32-2) (22-3) - 3(2x++) (2₂+4) 2 5=(x-7) + (3x+2) (= 5(2x-4) (2x+2) 구 x 8 = 5(3x+4)²- 3 (52-2)² 9 = (3x-4)² = (x+4) ²+₂ (2-4)² = (5x+4)²-(2x-4)²