Sagot :
H= (x-9) (x+1) + (x-2) (x-9)
(x-9) en facteur commun
H = (x-9) [(x+1) + (x-2)]
= (x-9) (2x-1)
et
I = (x-5) (2x+3) - (x +1) (x -5)
= (x-5) [(2x+3) - (x+1)]
= (x-5) (x+2)
Bonjour,
Factoriser:
H= (x-9) (x+1) + (x-2) (x-9)
H= (x-9)(x+1+x-2)
H= (x-9)(2x-1)
I = (x-5) (2x+3) - (x +1) (x -5)
I= (x-5)(2x+3-x-1)
I= (x-5)(x+2)