bonsoir
f (x) = 4 ( x - 1 )² - 1
f (x) = 4 ( x² - 2 x + 1 ) - 1
= 4 x² - 8 x + 4 - 1
= 4 x² - 8 x + 3
( 2 x - 3 ) ( 2 x - 1 )
= 4 x² - 2 x - 6 x + 3
= 4 x² - 8 x + 3
A (1) = 4 *1² - 8 *1 + 3 = 4 - 8 + 3 = - 1 donc A ∉ courbe
f (2 ) = 4 * 4 - 8 *2 + 3 = 16 - 16 + 3 = 3
( 2 x - 3 ) ( 2 x - 1 ) = 0
x = 3/2 ou 1 /2
f (x) = 3
4 x² - 8 x + 3 = 3
4 x² - 8 x = 0
x ( x - 8 ) = 0
x = 0 ou 8