Bonjour,
On cherche AE = AB = BD = ED
Pythagore:
AF² = EF² + AE²
AF² - FE² = AE²
100² - 60² = AE²
10 000 -3 600 =6 400
AE = √6 400 = 80
On cherche CD :
Pythagore: CD² = BC² + BD²
CD² = 60² + 80²
CD² = 3 600 = 6 400 = 10 000
CD = √10 000 = 100
parcours:
80 + 60 +100+80+60+100
=>480m
4 tours:
4 * 480 =>1 920m
