Bonjour,
Résoudre:
(2x-1)²-(x+1)² ≤ 0
(2x-1-x-1)(2x-1+x+1) ≤ 0
(x-2)(3x) ≤ 0
x= 0 et x= 2
S= [ 0; 2 ]
x²-2 ≤ (√2 + x)(x+1)
x²-2 ≤ √2x+ √2+ x²+x
-√2x-x ≤ √2 +2
x( -√2 - 1) ≤ √2+2
x ≥ (√2+2) /( -√2 - 1)
x ≥ (2/(-1-√2))+ (√2/(-1-√2))
x ≥ - √2
S= [-√2; +∞ [
