👤

Sagot :

INEQUATION

Bonjour,

Résoudre:

(2x-1)²-(x+1)² ≤ 0

(2x-1-x-1)(2x-1+x+1) ≤ 0

(x-2)(3x) ≤ 0

x= 0  et x= 2

S= [ 0; 2 ]

x²-2 ≤ (√2  + x)(x+1)

x²-2 ≤ √2x+ √2+ x²+x

-√2x-x ≤ √2 +2

x( -√2 - 1) ≤ √2+2

x ≥ (√2+2) /( -√2 - 1)

x ≥ (2/(-1-√2))+ (√2/(-1-√2))

x ≥ - √2

S= [-√2; +∞ [

Other Questions

© 2024 IDNLearn. All rights reserved.