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Sagot :

a (2x+1)(x+4)+(x+4)(3-5x)=0

(x+4) [(2x+1) + (3-5x)] = 0

(x+4) (-3x+4) = 0

soit x = - 4 soit x = 4/3

b 4x²+8x+4=0

(2x+2)² = 0 ; x = -1

c (3-2x)(5-x)(6+10x)=0

3 solutions

x= 3/2

x=5 ou x = -10/6=-5/3

20HSHSN05

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