Bonjour,
Sauf erreur d'énoncé :
a) 3x + 1 = 5x ⇔ 5x - 3x = 1 ⇔ 2x = 1 ⇔ x = 1/2
b) 2(x + 1) - 3(x – 7) = 1
⇔ 2x + 2 - 3x + 21 = 1
⇔ - x + 23 = 1
⇔ x = 23 - 1
⇔ x = 22
c) 3(x - 4) = 4(x + 4)
⇔ 3x - 12 = 4x + 16
⇔ 4x - 3x = - 12 - 16
⇔ x = - 28
d) 5[2(3 – x) - 2]= 5x + 1
⇔5[6 - 2x - 2] = 5x + 1
⇔5(-2x + 4) = 5x + 1
⇔-10x + 20 = 5x + 1
⇔5x + 10x = 20 - 1
⇔15x = 19
⇔x = 19/5