Réponse:
exo4
1a) f(0)=30 <> a×e⁰+180=30
a=30-180
a=-150
1b) f(10)= 60 <> a×e¹⁰b+180=60
-150×e¹⁰b=60-180
-150×e¹⁰b= -120
e¹⁰b=120/150
e¹⁰b=0,8
2a) f(t)=-150e‐⁰'⁰²²t+180
f'(t) =-0,022t(-150e‐⁰'⁰²²t)
f'(t) =3,3e‐⁰'⁰²²t
2b)
