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Sagot :

INEQUATION

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Résoudre:

ln(x+2)+ln(x)=ln(3)

ln (x+2)(x)) =ln(3)

ln(x²+2x)= ln (3)

x²+2x= 3

x²+2x-3= 0

Δ=2²-4(1)(-3)= 16 > 0

x1= (-2-4)/2= -6/2= -3

x2= (-2+4)/2= 2/2= 1

x2= 1, x∈ [ 0; + ∞ [

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