Réponse:
C)
[tex] \frac{3x + 2}{2x - 1} [/tex]
[tex]3x + 2 = - 3(2x - 1) \\ 3x + 2 = - 6x + 3 \\ 3x + 6x = 3 - 2 \\ 9x = 1 \\ x = \frac{1}{9} [/tex]
D)
[tex] \frac{3 {x}^{2} + 1}{x - 2} = 3x \\ 3 {x}^{2} + 1 = 3x(x - 2) \\ 3 {x}^{2} + 1 = 3 {x}^{2} - 6x \\ 1 = - 6x \\ - 6x = 1 \\ x = \frac{ - 1}{6} [/tex]
