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Sagot :

Explications étape par étape :

(x - 3 ) ( 2x + 1 ) ≤ ( 5 - x ) ( 2x + 1 )

2x² + x - 6x - 3 ≤ 10x + 5 - 2x² - x

2x² - 5x - 3 ≤ -2x² + 9x + 5

4x² - 14x - 8 ≤ 0

2x² - 7x - 4 ≤ 0               (  /2 )

             

Δ = (-7)² - 4 . 2 (-4)

⇔ Δ = 49 + 32 = 81

Δ > 0

x₁ = ( 7 - √81 ) / 4 = -2/4 = -1/2

x₂ = ( 7 + √81 ) / 4 = 16/4 = 4

S = [ -1/2 ; 4 ]

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