Sagot :

maudmarine

Bonjour

7x + 3 = - 4 + 7(x + 1)

7x + 3 = - 4 + 7x + 7

7x - 7x = - 4 + 7 - 3

0x = 0 → Une infinité de solutions

b. 2(x - 1) = x + 3 + x​

2x + 2 = x + 3 + x

2x - x - x = 3 - 2

0x = 1 → Equation impossible.