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Sagot :

1) A=

[tex] \sqrt{9} = \sqrt{3 ^{2} } = 3[/tex]

B=

[tex] \sqrt{4} + \sqrt{49} \\ = \sqrt{ {2}^{2} } + \sqrt{ {7}^{2} } \\ = 2 + 7 \\ = 9 [/tex]

C=

[tex] \sqrt{64} + \sqrt{36} \\ = \sqrt{ {8}^{2} } + \sqrt{ {6}^{2} } \\ = 8 + 6 \\ = 14[/tex]

2) A=

[tex] \sqrt{18} \\ = \sqrt{9 \times 2} \\= \sqrt{ {3}^{2} \times 2} \\ = 3 \sqrt{2} [/tex]

B=

[tex] \sqrt{200} \\ = \sqrt{100 \times 2} \\ = \sqrt{ {10}^{2} \times 2} \\ = 10 \sqrt{2} [/tex]

C=

[tex] \sqrt{125 } \\ = \sqrt{ {5}^{3} } \\ = \sqrt{ {5}^{2} \times 5 } \\ = 5 \sqrt{5} [/tex]

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