Sagot :
Bonsoir,
[tex]2(x+3) = 2x+6\\ -3x(x+5) = -3x^2-15x\\ -2(x-6) = -2x+12\\ 3a(x-2) = 3ax-6a\\ x(2-5x) = 2x-5x^2 = 5x^2-2x\\ 2{,}5y(-4-0{,}2y) = -10y-0{,}5y\\ -\frac{2}{3}\left(x-6\right) = -\frac{2}{3}x+4\\ -5b(-a+b) = 5ab-5b^2\\ -\frac{5}{7}a\left(3-\frac{7}{4a}\right) = -\frac{15}{7}a+\frac{5}{4}[/tex]