Bonsoir,
Résoudre l'équation :
[tex]\blue { 2x } (2x - 3) = {x}^{2} - 6x \\ \blue { 2x } \times 2x + \blue { 2x } \times ( - 3) = {x}^{2} - 6x \\ {4x}^{2} - 6x = {x}^{2 } - 6x[/tex]
[tex] {4x}^{2} - 6x + 6x = {x}^{2} - 6x + 6x \\ {4x}^{2} = {x}^{2} \\ {4x}^{2} - {x}^{2} = {x}^{2} - {x}^{2} \\ {3x}^{2} = 0 \\ \frac{ {3x}^{2} }{3} = \frac{0}{3} \\ {x}^{2} = 0 \\ x = \sqrt{0} \\ \blue { \boxed{ \green {\boxed{ \green { x = 0} } } } } [/tex]
Bonne soirée.
