Réponse:
I = 3x + 6y
= 3×x + 3×2y
I = 3(x + 2y)
J = 2ab - 4a + 12abc
= 2a × b - 2a × 2 + 2a × 6bc
J = 2a (b -2 + 6bc)
K = (x - 5) (2x + 1) - (x - 5) (3x + 7)
= (x - 5) (2x + 1 - 3x - 7)
= (x - 5) (-x - 6)
K = - (x - 5) (x + 6)
L = (2x - 3) (2x - 3)
M = (5x - 9) (5x + 9)
