Sagot :

Bonjour,

a) 3x +5 < 5x - 10

5+10 < 5x -3x

15 < 2x

x >  15/2

x > 7,5

b) 12x -7 < 10x + 3

12x-10x < 3+7

2x < 10

x < 10/2

x < 5

inequation

Bonjour,

Résoudre:

a) 3x +5 < 5x - 10

3x-5x < -10-5

-2x < -15

x  > 15/2

S= ] 15/2; +∞ [

b) 12x -7 < 10x + 3

12x-10x < 3+7

x < 10/2

x < 5

S= ] -∞; 5 [